Simple java program?

Can someone give me a little java program i can attempt nothing to big but something kind of simple.
I really want to get better.

Something like this : http://forum.logicalgamers.com/programming/48074-program-help.html

lol make me a Java calculator with advanced functions and/or make a Java calculator that has a GUI.

Make a browser with bookmarks.

The Unintelligible wrote:

lol make me a Java calculator with advanced functions and/or make a Java calculator that has a GUI.

Last night i made a simple calculator that does addition subtraction multiplication and division took me a while lol.
What else should i add on to it? Also what is GUI?

As in a dialog or window as the interface for the program.

Graphical user interface - Wikipedia, the free encyclopedia

Try making a two player rock-paper-scissors game. Seems simple enough.

The Unintelligible wrote:

As in a dialog or window as the interface for the program.

Graphical user interface - Wikipedia, the free encyclopedia

Try making a two player rock-paper-scissors game. Seems simple enough.

Ill try to make the rock paper scissors game later. Sounds like fun.

So this how far i came with the rock-paper-scissors game:

import javax.swing.JOptionPane;



/**

 * @(#)RockPaperScissors.java

 *

 * RockPaperSissors application

 *

 * @author 

 * @version 1.00 2013/3/8

 */

 

public class RockPaperScissors {

    

    public static void main(String[] args) {

    	

    	int rps;

    	int rps2;

    	String input;

    	

    	

    	input = JOptionPane.showInputDialog("Player one: \n 1 - Rock \n 2 - Paper \n 3 - Scissors");

    	rps = Integer.parseInt(input);

    	

    	input = JOptionPane.showInputDialog("Player one: \n 1 - Rock \n 2 - Paper \n 3 - Scissors");

    	rps2 = Integer.parseInt(input);

    	

    	if(rps == 1 && rps2 == 3)

    		JOptionPane.showMessageDialog(null, "Player 1 wins!");

    		

    	else if(rps == 1 && rps2 == 2)

    		JOptionPane.showMessageDialog(null, "Player 2 wins!");

    		

    	else if(rps == 1 && rps2 == 1)

    		JOptionPane.showMessageDialog(null, "It was a tie!");

    		

    	else if(rps == 2 && rps2 == 1)

    		JOptionPane.showMessageDialog(null, "Player 1 wins!");

    		

    	else if(rps == 2 && rps2 == 2)

    		JOptionPane.showMessageDialog(null, "It was a tie!");

    		

    	else if(rps == 2 && rps2 == 3)

    		JOptionPane.showMessageDialog(null, "Player 2 wins!");

    		

    	else if(rps == 3 && rps2 == 1)

    		JOptionPane.showMessageDialog(null, "Player 2 wins!");

    		

    	else if(rps == 3 && rps2 == 2)

    		JOptionPane.showMessageDialog(null, "Player 1 wins!");

    		

    	else if(rps == 3 && rps2 == 3)

    		JOptionPane.showMessageDialog(null, "It was a tie!");

    		

    	else

    		JOptionPane.showMessageDialog(null, "You did not enter 1, 2 or 3!");

    		

    		

    

    		

    

    	

 

    	

    	System.exit(0);

    	

    }

}

I was wondering how can i make it loop?
Ask if they wanna play again and make it go back to the beginning?

Just wrap up the code you used to make the game in a while loop.

while (true)
{
// statement(s)
}


Then put a breaking clause after the game is over instead of the exit procedure. Something that asks for input. (i.e. "Do you want to play again?" If answer == 'y' then continue loop else exit program.)

The Unintelligible wrote:

Just wrap up the code you used to make the game in a while loop.

while (true)
{
// statement(s)
}


Then put a breaking clause after the game is over instead of the exit procedure. Something that asks for input. (i.e. "Do you want to play again?" If answer == 'y' then continue loop else exit program.)

Can you make it a bit more simpler?
Show me.

Something like this:

import javax.swing.JOptionPane;

/**
* @(#)RockPaperScissors.java
*
* RockPaperSissors application
*
* @author
* @version 1.00 2013/3/8
*/

public class RockPaperScissors {

public static void main(String[] args) {

int rps;
int rps2;
String input;

while (true)
{
input = JOptionPane.showInputDialog("Player one: \n 1 - Rock \n 2 - Paper \n 3 - Scissors");
rps = Integer.parseInt(input);

input = JOptionPane.showInputDialog("Player one: \n 1 - Rock \n 2 - Paper \n 3 - Scissors");
rps2 = Integer.parseInt(input);

if(rps == 1 && rps2 == 3)
JOptionPane.showMessageDialog(null, "Player 1 wins!");

else if(rps == 1 && rps2 == 2)
JOptionPane.showMessageDialog(null, "Player 2 wins!");

else if(rps == 1 && rps2 == 1)
JOptionPane.showMessageDialog(null, "It was a tie!");

else if(rps == 2 && rps2 == 1)
JOptionPane.showMessageDialog(null, "Player 1 wins!");

else if(rps == 2 && rps2 == 2)
JOptionPane.showMessageDialog(null, "It was a tie!");

else if(rps == 2 && rps2 == 3)
JOptionPane.showMessageDialog(null, "Player 2 wins!");

else if(rps == 3 && rps2 == 1)
JOptionPane.showMessageDialog(null, "Player 2 wins!");

else if(rps == 3 && rps2 == 2)
JOptionPane.showMessageDialog(null, "Player 1 wins!");

else if(rps == 3 && rps2 == 3)
JOptionPane.showMessageDialog(null, "It was a tie!");

else
JOptionPane.showMessageDialog(null, "You did not enter 1, 2 or 3!");

input = JOptionPane.showInputDialog("Do you wish to play again? [y/n]");

if (input == 'y')
// Continue Loop
else if (input == 'n')
System.exit(0);

}


}
}