Simple java program?

[Taz]

Can someone give me a little java program i can attempt nothing to big but something kind of simple.
I really want to get better.

Something like this : http://forum.logicalgamers.com/progr...gram-help.html

[The Unintelligible]

lol make me a Java calculator with advanced functions and/or make a Java calculator that has a GUI.

[ya bish]

Make a browser with bookmarks.

[Taz]

lol make me a Java calculator with advanced functions and/or make a Java calculator that has a GUI.

Last night i made a simple calculator that does addition subtraction multiplication and division took me a while lol.
What else should i add on to it? Also what is GUI?

[The Unintelligible]

As in a dialog or window as the interface for the program.

Graphical user interface - Wikipedia, the free encyclopedia

Try making a two player rock-paper-scissors game. Seems simple enough.

[Taz]

As in a dialog or window as the interface for the program.

Graphical user interface - Wikipedia, the free encyclopedia

Try making a two player rock-paper-scissors game. Seems simple enough.

Ill try to make the rock paper scissors game later. Sounds like fun.

[Taz]

So this how far i came with the rock-paper-scissors game:

import javax.swing.JOptionPane;

/**
 * @(#)RockPaperScissors.java
 *
 * RockPaperSissors application
 *
 * @author 
 * @version 1.00 2013/3/8
 */
 
public class RockPaperScissors {
    
    public static void main(String[] args) {
    	
    	int rps;
    	int rps2;
    	String input;
    	
    	
    	input = JOptionPane.showInputDialog("Player one: \n 1 - Rock \n 2 - Paper \n 3 - Scissors");
    	rps = Integer.parseInt(input);
    	
    	input = JOptionPane.showInputDialog("Player one: \n 1 - Rock \n 2 - Paper \n 3 - Scissors");
    	rps2 = Integer.parseInt(input);
    	
    	if(rps == 1 && rps2 == 3)
    		JOptionPane.showMessageDialog(null, "Player 1 wins!");
    		
    	else if(rps == 1 && rps2 == 2)
    		JOptionPane.showMessageDialog(null, "Player 2 wins!");
    		
    	else if(rps == 1 && rps2 == 1)
    		JOptionPane.showMessageDialog(null, "It was a tie!");
    		
    	else if(rps == 2 && rps2 == 1)
    		JOptionPane.showMessageDialog(null, "Player 1 wins!");
    		
    	else if(rps == 2 && rps2 == 2)
    		JOptionPane.showMessageDialog(null, "It was a tie!");
    		
    	else if(rps == 2 && rps2 == 3)
    		JOptionPane.showMessageDialog(null, "Player 2 wins!");
    		
    	else if(rps == 3 && rps2 == 1)
    		JOptionPane.showMessageDialog(null, "Player 2 wins!");
    		
    	else if(rps == 3 && rps2 == 2)
    		JOptionPane.showMessageDialog(null, "Player 1 wins!");
    		
    	else if(rps == 3 && rps2 == 3)
    		JOptionPane.showMessageDialog(null, "It was a tie!");
    		
    	else
    		JOptionPane.showMessageDialog(null, "You did not enter 1, 2 or 3!");
    		
    		
    
    		
    
    	
 
    	
    	System.exit(0);
    	
    }
}

I was wondering how can i make it loop?
Ask if they wanna play again and make it go back to the beginning?

[The Unintelligible]

Just wrap up the code you used to make the game in a while loop.

while (true)
{
// statement(s)
}


Then put a breaking clause after the game is over instead of the exit procedure. Something that asks for input. (i.e. "Do you want to play again?" If answer == 'y' then continue loop else exit program.)

[Taz]

Just wrap up the code you used to make the game in a while loop.

while (true)
{
// statement(s)
}


Then put a breaking clause after the game is over instead of the exit procedure. Something that asks for input. (i.e. "Do you want to play again?" If answer == 'y' then continue loop else exit program.)

Can you make it a bit more simpler?
Show me.

[The Unintelligible]

Something like this:

import javax.swing.JOptionPane;

/**
* @(#)RockPaperScissors.java
*
* RockPaperSissors application
*
* @author
* @version 1.00 2013/3/8
*/

public class RockPaperScissors {

public static void main(String[] args) {

int rps;
int rps2;
String input;

while (true)
{
input = JOptionPane.showInputDialog("Player one: \n 1 - Rock \n 2 - Paper \n 3 - Scissors");
rps = Integer.parseInt(input);

input = JOptionPane.showInputDialog("Player one: \n 1 - Rock \n 2 - Paper \n 3 - Scissors");
rps2 = Integer.parseInt(input);

if(rps == 1 && rps2 == 3)
JOptionPane.showMessageDialog(null, "Player 1 wins!");

else if(rps == 1 && rps2 == 2)
JOptionPane.showMessageDialog(null, "Player 2 wins!");

else if(rps == 1 && rps2 == 1)
JOptionPane.showMessageDialog(null, "It was a tie!");

else if(rps == 2 && rps2 == 1)
JOptionPane.showMessageDialog(null, "Player 1 wins!");

else if(rps == 2 && rps2 == 2)
JOptionPane.showMessageDialog(null, "It was a tie!");

else if(rps == 2 && rps2 == 3)
JOptionPane.showMessageDialog(null, "Player 2 wins!");

else if(rps == 3 && rps2 == 1)
JOptionPane.showMessageDialog(null, "Player 2 wins!");

else if(rps == 3 && rps2 == 2)
JOptionPane.showMessageDialog(null, "Player 1 wins!");

else if(rps == 3 && rps2 == 3)
JOptionPane.showMessageDialog(null, "It was a tie!");

else
JOptionPane.showMessageDialog(null, "You did not enter 1, 2 or 3!");

input = JOptionPane.showInputDialog("Do you wish to play again? [y/n]");

if (input == 'y')
// Continue Loop
else if (input == 'n')
System.exit(0);

}


}
}