Thanks for all the help guys.
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Thread: Help with math? [reward in LG~]
- 26 Nov. 2009 03:01am #1
Help with math? [reward in LG~]
Last edited by Kinoshu; 26 Nov. 2009 at 07:31am.
L O L W U T
- 26 Nov. 2009 03:02am #2
Use wolfram.
Find your main information, extract it from the words.
Plug it in.
- 26 Nov. 2009 03:02am #3
Do your own damn math homework. I have my own homework trk on >_>
- 26 Nov. 2009 03:07am #4
1. 5 and 1
I'll do the rest right now and edit in this post.
Minora- That's not what he asked for D<
- 26 Nov. 2009 03:09am #5
The answer to the first question is supposed to be 13 and 13, but I don't know how my teacher got that answer.
L O L W U T
- 26 Nov. 2009 03:17am #6
- 26 Nov. 2009 03:19am #7
- 26 Nov. 2009 03:29am #8
I'll try the last one.
(x)^2+(X+2)^2=452
(x^2)+(X^2+4x+4)=452
2(x^2)+4x+4=452
-452 -452
2(X^2)+4x-448=0
The roots of the quadratic formula are 14 and -16.
Using 14, (14^2)+(16^2)=452
Using -16, (-16^2)+(-14^2)=452.
The answer is 14 and 16 or -14 and -16.LG's resident grammar nazi.
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- 26 Nov. 2009 03:42am #9
Thanks. =)
Sent you the gold~L O L W U T
- 26 Nov. 2009 05:21am #10
The first is 13 and 13, because all other combinations of numbers, when squared, are greater than 169+169.
e.g. 25 and 1 = 26, but 25^2 + 1^2 > 13^2 + 13^2. And this is true for all possible values that add up to 26, because the larger a number is, the larger the difference is, exponentially. In other words, the difference between 14^2 and 13^2 is greater than the difference between 13^2 and 12^2. So the small one gets, the larger the other gets, and thus the larger the addition of the two squares becomes (because of the larger number). 13 and 13 are as small as the squares can get. If one increases (even if the other decreases), the sum of the squares increases too.
There isn't an equation for this, unless you can graph.
Y = X^2 + (26 - X)^2
And find the minimum.