Help with math? [reward in LG~]

Thanks for all the help guys.

Use wolfram.
Find your main information, extract it from the words.
Plug it in.

Do your own damn math homework. I have my own homework trk on >_>

1. 5 and 1

I'll do the rest right now and edit in this post.
Minora- That's not what he asked for D<

The answer to the first question is supposed to be 13 and 13, but I don't know how my teacher got that answer.

Kinoshu wrote:

The answer to the first question is supposed to be 13 and 13, but I don't know how my teacher got that answer.

Their squares are decimals though D;

NotNeccesary wrote:

Their squares are decimals though D;

That would be their square roots.
The square of 13 is 169.
So I guess the minimum [of the..parabola?] is 338. But I totally fail and have no idea how to make an equation out of that.

I'll try the last one.

(x)^2+(X+2)^2=452
(x^2)+(X^2+4x+4)=452
2(x^2)+4x+4=452
-452 -452

2(X^2)+4x-448=0
The roots of the quadratic formula are 14 and -16.
Using 14, (14^2)+(16^2)=452
Using -16, (-16^2)+(-14^2)=452.
The answer is 14 and 16 or -14 and -16.

Thanks. =)
Sent you the gold~

The first is 13 and 13, because all other combinations of numbers, when squared, are greater than 169+169.
e.g. 25 and 1 = 26, but 25^2 + 1^2 > 13^2 + 13^2. And this is true for all possible values that add up to 26, because the larger a number is, the larger the difference is, exponentially. In other words, the difference between 14^2 and 13^2 is greater than the difference between 13^2 and 12^2. So the small one gets, the larger the other gets, and thus the larger the addition of the two squares becomes (because of the larger number). 13 and 13 are as small as the squares can get. If one increases (even if the other decreases), the sum of the squares increases too.
There isn't an equation for this, unless you can graph.
Y = X^2 + (26 - X)^2
And find the minimum.