How do you find the Equation of AB in standard form?
Point A= (-16,14)
Point B= (3,6)
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How do you find the Equation of AB in standard form?
Point A= (-16,14)
Point B= (3,6)
kadfhjkhdzfkjshdkfjhskjdhfkjsfgsfdgQuote:
Originally Posted by Areox2
Are you looking for a line?
Find the slope, first.
y = mx + b
The slope is, for every X the line travels horizontally, it travels Y vertically.
So, we take the total Y that it travels:
Point A: (-16, 14)
Point B: (3, 6)
6 - 14 = -8
It started at 14, decreased to 6, therefore it decreased a total of 8.
Now, we find how long it took for it to decrease by 8.
Point A: (-16, 14)
Point B: (3, 6])
3 - -16 = 3 + 16 = 19
So, after moving 19 units horizontally, the Y value shifted by -8.
So for every 19, it shifts -8.
In ratio form, that's -8/19 (literally, -8 for every 19).
y = (-8/19)x + b
And I'm going to stop there, 'cause I don't feel like remembering how to find B, and I assume this isn't what you're trying to do anyway, 'cause this is Algebra I material. >_>
I'll pay you if you help me and not give me a site =_=
Is what I posted what you're looking for?Quote:
Originally Posted by NotNeccesary
Yeah.
Damn I've always been bad at graphing :[
we're doing the bowtie project whatever.
Algebra 2? My Algebra 1 teacher covered this.
-0.42105263157894735 according to Find Distance, Slope and Equation of Line - Calculator
-0.42105263157894735 according to
Slope and Distance Calculator
Your welcome
Not sure what that is. Graphing is easy. You just gotta think about it the right way. I tried to explain it the way I comprehend graphs.
For example, miles per hour. 60mph means 60 miles for every 1 hour. That is 60 for every 1. The slope of 60mph would be 60. So in X=1 hours, Y=60 miles. X=2 hours, Y=120 miles.
Now for b.
y = (-8/19)x + b
b is calculated by using X = 0, because when X is zero, m doesn't matter, because mx = m * 0 = 0, leaving you with y = m * 0 + b = 0 + b = b.
y = b when x = 0
So, to find what b is, we find what y is when x is zero, given what we already know.
I'm going to use Point A, since it's easier to count forwards than backwards.
Point A: (-16, 14)
y = (-8/19)x + b
We are currently (at Point A) 16 units away from X = 0. And we know that for every unit, we're going to decrease by 8/19. So, 16 * -8/19 = -128/19. So, 16 units away from Point A, the Y value should have decreased by 128/19 (that is, 16 of -8/19).
At Point A, the Y value is 14. 128/19 less than that is 14 - 128/19 = 266/19 - 128/19 (converted 14 to 266/19 so that we can subtract fractions) = (266 - 128)/19 = 138/19
So the Y value 16 units ahead of Point A is 138/19. That is, the Y value 16 units ahead of X = -16, or the Y value at X = 0, is 138/19.
And since the Y value at X = 0 is b, because:
y = mx + b = m * 0 + b = 0 + b = b
Then y = 138/19 = b. So, b = 138/19
y = mx + b = (-8/19)x + 138/19
This would be so much easier to teach if we had whole numbers.